Post by Calvin on Apr 17, 2011 9:30:47 GMT -5
Well since you're here, I assume you are ready for the following...
A calculation of the chance of encountering a SHINY Pikachu
It's just somebasic advance Mathematics in my opinion on probability.
First off, some basic facts:
Rate of a Pikachu being SHINY = 0.01%
Number of PIkachu per wave = 5
Number of waves per run = 30
Rate of a Pikachu wave = 1%
Number of runs to encounter a Pikachu wave = 10/3
Next, on to the probability calculations:
Probability of encountering 'n' Pikachus in a row that are NOT SHINY = (0.9999)n
Probability of encountering a SHINY Pikachu within 'n' Pikachus = 1-(0.9999)n
Therefore, when (0.9999)n = 0.01,
We can get the number of Pikachus required to be encountered in order to have a 99% chance of finding a SHINY Pikachu within them.
To find n, we take log0.99990.01
= 46049 (corrected to the nearest integer)
Lastly, some simple calculations:
Number of waves to encounter 46049 Pikachus = 9210 (Corrected to the nearest integer)
Number of runs to encounter 9210 waves = 30700
Assume the time to complete VT 2 = 2.5 min
Time to find a SHINY Pikachu
= 76750 mins
= 1279 hours (corrected to nearest integer)
= 53 days of non stop SHINY Pikachu Hunting (corrected to nearest integer)
Conclusion:
Too all Shiny Pikachu Hunters out there, you are warned!
Remember, this 53 days is the Maximum
amount of time you have to spend to catch a SHINY Pikachu. If you're lucky , you can even get one on your first try within minutes.
Well good luck guys. (Though the enthusiasm seems to have died down)
Credits tome, myself, and I Mysticman89
For all his help and mighty calculations.
I simply summarised them here.
Sidenote: Sorry it took me so long to edit the post, my brain experienced an overload of information while processing your explanation.
By the way please correct me if I am wrong.
Hopefully not :X
This only applies to VT 2
And I believe 99% of the caught SHINY Pikachu out there are gotten through hacking.
The reason my old calculation was not accurate was because I assumed from 0.01% that one is guaranteed to encounter a shiny pikachu as his 10000th pikachus.
While Mysticman89 calulation took into consideration of the chance of encountering a shiny pikachu WITHIN 10000 pikachus.
Some of you may think that the days should be shorten if this is the case and this is because my assumption was dead wrong, resulting in a FAR FROM ACCURATE result.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Old post - In case it's needed for future reference
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hi guys,
Here are some facts to answer your doubts.
This only apply to vf2
Rate of a Pikachu being SHINY = 0.01%
Number of Pikachu per wave = 5
Number of wave to find a SHINY Pikachu = 2000
Rate of a Pikachu wave = 1%(wave rate) * 30(total no. of waves)
= 1 wave in 10/3 runs
Change of meeting a SHINY Pikachu =10/3 * 2000
= 6666 RUNS!
Estimated time to catch 1 SHINY Pikachu
=6666(runs) * 2mins(time to complete vt2) / 60mins(1 hour)
= 222 hours
= 9.25 days of hardcore screen staring
A calculation of the chance of encountering a SHINY Pikachu
It's just some
First off, some basic facts:
Rate of a Pikachu being SHINY = 0.01%
Number of PIkachu per wave = 5
Number of waves per run = 30
Rate of a Pikachu wave = 1%
Number of runs to encounter a Pikachu wave = 10/3
Next, on to the probability calculations:
Probability of encountering 'n' Pikachus in a row that are NOT SHINY = (0.9999)n
Probability of encountering a SHINY Pikachu within 'n' Pikachus = 1-(0.9999)n
Therefore, when (0.9999)n = 0.01,
We can get the number of Pikachus required to be encountered in order to have a 99% chance of finding a SHINY Pikachu within them.
To find n, we take log0.99990.01
= 46049 (corrected to the nearest integer)
Lastly, some simple calculations:
Number of waves to encounter 46049 Pikachus = 9210 (Corrected to the nearest integer)
Number of runs to encounter 9210 waves = 30700
Assume the time to complete VT 2 = 2.5 min
Time to find a SHINY Pikachu
= 76750 mins
= 1279 hours (corrected to nearest integer)
= 53 days of non stop SHINY Pikachu Hunting (corrected to nearest integer)
Conclusion:
Too all Shiny Pikachu Hunters out there, you are warned!
Remember, this 53 days is the Maximum
amount of time you have to spend to catch a SHINY Pikachu. If you're lucky , you can even get one on your first try within minutes.
Well good luck guys. (Though the enthusiasm seems to have died down)
Credits to
For all his help and mighty calculations.
I simply summarised them here.
Sidenote: Sorry it took me so long to edit the post, my brain experienced an overload of information while processing your explanation.
By the way please correct me if I am wrong.
Hopefully not :X
This only applies to VT 2
And I believe 99% of the caught SHINY Pikachu out there are gotten through hacking.
The reason my old calculation was not accurate was because I assumed from 0.01% that one is guaranteed to encounter a shiny pikachu as his 10000th pikachus.
While Mysticman89 calulation took into consideration of the chance of encountering a shiny pikachu WITHIN 10000 pikachus.
Some of you may think that the days should be shorten if this is the case and this is because my assumption was dead wrong, resulting in a FAR FROM ACCURATE result.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Old post - In case it's needed for future reference
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hi guys,
Here are some facts to answer your doubts.
This only apply to vf2
Rate of a Pikachu being SHINY = 0.01%
Number of Pikachu per wave = 5
Number of wave to find a SHINY Pikachu = 2000
Rate of a Pikachu wave = 1%(wave rate) * 30(total no. of waves)
= 1 wave in 10/3 runs
Change of meeting a SHINY Pikachu =10/3 * 2000
= 6666 RUNS!
Estimated time to catch 1 SHINY Pikachu
=6666(runs) * 2mins(time to complete vt2) / 60mins(1 hour)
= 222 hours
= 9.25 days of hardcore screen staring